2×{(13-7+2)÷(2×1+2)-40}÷2
Answers
Answered by
3
ANSWER.
*RULE.*
*BODMAS*
B = Bracket . [ ] ,{ }, ( )
O = Of ( it is also like a multiplication)
D = Divide ÷
M = Multiple. ×
A =Add. +
S= Substract. -
QUESTION
2×{(13-7+2)÷(2×1+2)-40}÷2
ANSWER.
STEP BY STEP SOLUTION.
STEP (1)
SOLVE BRACKET.
SMALL BRACKET FIRST.
IN SMALL BRACKET
2×{(13-7+2)÷(2×1+2)-40}÷2
= 2×{(13-5)÷(2+2)-40}÷2
= 2×{8÷4-40}÷2
STEP (2)
SOLVE { } BRACKET
= 2×{2-40}÷2
=2×(-38)÷2
STEP (3). SOLVE DIVIDED
= 2×(-19)
=-38 Ans
*RULE.*
*BODMAS*
B = Bracket . [ ] ,{ }, ( )
O = Of ( it is also like a multiplication)
D = Divide ÷
M = Multiple. ×
A =Add. +
S= Substract. -
QUESTION
2×{(13-7+2)÷(2×1+2)-40}÷2
ANSWER.
STEP BY STEP SOLUTION.
STEP (1)
SOLVE BRACKET.
SMALL BRACKET FIRST.
IN SMALL BRACKET
2×{(13-7+2)÷(2×1+2)-40}÷2
= 2×{(13-5)÷(2+2)-40}÷2
= 2×{8÷4-40}÷2
STEP (2)
SOLVE { } BRACKET
= 2×{2-40}÷2
=2×(-38)÷2
STEP (3). SOLVE DIVIDED
= 2×(-19)
=-38 Ans
Answered by
0
Answer:
Step-by-step explanation:
2×{(13-7+2)÷(2×1+2)-40}÷2
2×{8÷4-40}÷2
2×{2-40}÷2
2×(-38)÷2
2×(-19)
-38
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