Question

(2) 135
(b) 145
(c) 155
14 X 1 =4]
Q.20 Case Study4-
is
The triangular side walls of a flyover have been used for advertisements. The sides of the walls are
122 m, 22 m and 120 m. The advertisements yield an earning of Rs. 7000 per mper year. I
1. What is the semi perimeter of each wall?
a) 16 m
b) 528 m
c) 264 m
1.132 m
2. What is the area of each wall?
a) 1320 sq.m
b) 2640 sq.m
c) 660 sq.m
none of these
3. A company hired one of its walls for six months. How much rent did it pay?
a) Rs.9240000
b) Rs.7000
c) Rs.4620000
d) Rs. 3080000
4. If an altitude is drawn on the smallest side of the triangular wall, what will be the length of this
altitude?
a) 60m
b) 120m
c) 130m
d) 240m
d) None of these
5. What is the cost of fencing each wall at the rate of Rs. 4.50 per m.
a) Rs.59625
b) Rs. 1188​

Answer 1

Answer:

According to the question, The sides of the triangle are 13 m, 14 m and 15 m Let a = 13, b = 14, c = 15 s = (a + b + c)/2 ⇒ s = (13 + 14 + 15)/2 = 42/2 = 21. Area of triangle = √s(s-a)(s-b)(s-c) = √21(21-13)(21-14)(21-15) = √21×8×7×6 = 84m2 Cost of advertisements for a year = Area of triangle × Cost per m2 = 84×2000 = Rs. 168000 Since the board is rented for only 6 months: Cost of advertisements for 6 months = (6/12) × 168000 = Rs. 84000Read more on Sarthaks.com - https://www.sarthaks.com/875086/the-triangular-side-walls-flyover-have-been-used-advertisements-the-sides-the-walls-are-and

Step-by-step explanation:

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