Question

2.135 g of an organic compound was combusted in air to produce 3.080 g CO2 and 1.575 g H2O. If the molecular mass of the compound is 122 amu, calculate the molecular formula of the compound.​

Answer 1

Explanation:

x

H

y

+(x+

4

y

)O

2

→ xCO

2

+

2

y

H

2

O

Moles of H

2

O=

18

0.72

=0.04

Moles of CO

2

=

44

3.08

=0.07

2

y

=0.04×100 or y=8 , x=0.07 ×100=7

Empirical formula is C

7

H

8