Question

2,14,26,38...........28th term of this is
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Answer 1

$a = 2 \: \: \: \: \: \: \: \: \: \: d = 14 - 2 = 12 \\ \\ tn = a + (n - 1)d \\ \\ t28 = 2 + (8 - 1)12 \\ \\ t28 = 2 + 9 \times 12 \\ \\ t28 = 2 + 108 \\ \\ t28 = 110$

Answer 2

Answer:

$\begin{gathered}a = 2 \: \: \: \: \: \: \: \: \: \: d = 14 - 2 = 12 \\ \\ tn = a + (n - 1)d \\ \\ t28 = 2 + (8 - 1)12 \\ \\ t28 = 2 + 9 \times 12 \\ \\ t28 = 2 + 108 \\ \\ t28 = 110\end{gathered}a=2d=14−2=12tn=a+(n−1)dt28=2+(8−1)12t28=2+9×12t28=2+108t28=110$

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