Question

2. 144 L of liquid P and 216 L of liquid Q are to be packed in containers of the same
size. The minimum number of containers required are
(c) 10
(d) 15
(a) 6
(b) 5​

Answer 1

Answer:

i think it is option (d) 15

Step-by-step explanation:

if we combine both liquids together

it will form liquid of 360 Litres

then it can divide into 15 containers of same size

Answer 2

The correct option would be '(b) 5

Step-by-step explanation:

Given,

Quantity of liquid P = 144 L,

Quantity of liquid Q = 216 L,

If these two liquids are packed in containers of the same size,

Then for getting minimum number of container,

The quantity of liquid in each of such container = HCF( Quantity in P, Quantity in Q )

Since, 144 = 2 × 2 × 2 × 2 × 3 × 3

216 = 2 × 2 × 2 × 3 × 3 × 3

Thus, HCF(144, 216) = 2 × 2 × 2 × 3 × 3 = 72,

Thus, the quantity of liquid in each of such container = 72 liters,

$\because \text{Number of small containers}=\frac{\text{Quantity in large container}}{\text{Quantity in small container}}$

Hence, the minimum number of containers required = $\frac{144}{72}+\frac{216}{72}$

$=2 + 3$

= 5

i.e. option (b) is correct.

#Learn more:

72 litres of liquid A and 108 litres of liquid B are to be packed in containers of same size. find the minimum number of containers required.

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