Question

2х + Зу = -15
3х + 2y = -15
solve by substitution Method​

Answer 1

Let

$2x+3y = -15.....(i)$

$3x+2y = -15.....(ii)$

From equation (i)

$2x = -15-3y$

$x = \frac{-1}{2}(15+3y).....(iii)$

Substitute above value of x in equation (ii), we'll get

$3*\frac{-1}{2}(15+3y)+2y = -15$

$-3(15+3y) + 4y = -30$

$-45-9y+4y = -30$

$-5y = 15$

$y = -3$

Substitute above value of y in equation (iii), we'll get

$x = \frac{-1}{2}(15-9)$

$x = -3$

SO THE SOLUTION TO THE GIVEN PAIR OF LINEAR EQUATIONS IN TWO VARIABLES IS

$\huge\black\boxed{x = -3}$ AND $\huge\black\boxed{y = -3}$

Answer 2

Step by Step Explanation.