Question

2.15
Find the perimeter of a rhombus, the lengths of whose diagonals are
16cm and 30cm.

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Answer 1

Answer:

This follows pythagros theorem

8^2 + 15 ^2=c^2

64+225 =c^2

289=c^2

7=c

perimeter of rhombus is 4 sides

side 4*7 = 68

Answer 2

Answer:

here is ur ans

Step-by-step explanation:

first we will find the side of rhombus by Pythagoras theorem i.e

(Hypotenuse)^2 = (Base)^2 + ( height)^2

we will take half of both diagonals

( hypotenuse)^2 = (8)^2 + (15)^2

= 64 + 225

= 289

hypotenuse= √289

= 17 cm

all sides of rhombus = 17 cm

so now,

perimeter of rhombus = 4 X side

= 4 X 17

= 68 cm

(Therefore perimeter of rhombus is 68 cm.)

hope this helps u

thank u