Question

2.15 In ohm's experiment, the value of the unknown resistances were found to be 6.12, 6.24, 6.00,
5.88,and 5.76,ohm.Calculate the absolute error, relative error and percentage error in this
measurement.​

Answer 1

average

= (6.12 + 6.24 + 6.00 + 5.88 + 5.76)/5

= 29.30 / 5

= 5.86 ohm

Absolute error

|dx1| = 5.86 - 6.12 = 0.26

|dx2| = 5.86 - 6.24 = 0.38

|dx3| = 5.86 - 6.00 = 0.24

|dx4| = 5.86 - 5.88 = 0.02

|dx5| = 5.86 - 5.76 = 0.10

(0.26 + 0.38 + 0.24 + 0.02 + 0.10)/5

= 0.2

relative error = absolute error/actual number

= 0.2 / 5.86 = 0.0341

percentage error = relative error × 100%

=0.0341×100

= 3.41%

Please mark as brainliest