Question

2) 15. N2o5 decomposes to no2 and o2 and follows first order kinetics. After 50 minutes, the pressure inside the vessel increases from 50 mmhg to 87.5 mmhg. The pressure of the gaseous mixture after 100 minute at constant temperature will be: (1) 116.25 mmhg (2) 175.0 mmhg (3) 106.25 mmhg (4) 136.25 mmhg

Answer 1

answer is(3 ) 106.25 mmhg

sol           N2O5→2NO2+1/2O2

t=0              50         0        0

t=50min       50-p1  2p1    p1/2

        =25

t=100 min    50-p2   2P2     p2/2

  =12.5

50-p1+2p1+p1/2=87.5

50+3p1/2=87.5

3p1/2=37.5

p1=37.5×2/3=25

50min is half life period

 50-p2=12.5

p2=37.5 mmhg

total pressure at 100 min

=50-p2+2p2+p2/2

=50+3p2/2=50+3/2×37.5

=50+56.25

=106.25mmgh

hope it is helpful

Answer 2

JEE Mains 2019

Solution is in attachment

3) 106.25mm Hg ✔️