Question

2х + Зу = 17, 3х - 2y = 6 solve this by cross Multiplication method​

Answer 1

Answer:

4x+6y=34

9x-6y=18

=13x=52

x=4

2(4)+3y=17

y=3

Step-by-step explanation:

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Answer 2

• The value of x = 4 and y = 3

Given:

2х + Зу = 17,

• 2x + 3y - 17 = 0 ------(i)

And

3х - 2y = 6

• 3x - 2y - 6 = 0 -----(ii)

So,

From eq.(i), we get

• a₁ = 2 ; b₁ = 3 ; c₁ = (-17)

Form eq.(ii), we get

• a₂ = 3 ; b₂ = (-2) ; c₂ = (-6)

Now,

$\boxed{x = \frac{b_{1}c_{2} - b_{2}c_{1}}{a_{1}b_{2}-a_{2}b_{1}}}$

and

$\boxed{y = \frac{c_{1}a_{2} - c_{2}a_{1}}{a_{1}b_{2}-a_{2}b_{1}}}$

So,

$\bf{x = \dfrac{[3* (-6)] - [(-2)*(-17)]}{[2*(-2)]-[3 *3]}}$

$\bf{x = \dfrac{[-18] - [34]}{[-4]-[9]}}$

$\bf{x = \dfrac{-52}{-13}}$

Thus,

x = 4

Now,

$\bf{y = \dfrac{[(-17)*3] - [(-6)*2]}{[2*(-2)]-[3*3]}}$

$\bf{y = \dfrac{[-51] - [-12]}{[-4]-[9]}}$

$\bf{y = \dfrac{-51 +12}{-4-9}}$

$\bf{y = \dfrac{-39}{-13}}$

Thus,

y = 3