Question

2
17. If 20% of A= B and 40% of B= C, then 60% of (A+B) is:​

Answer 1

Answer:

let a=100,

then according to the question 20% of A=100×20/100=20 i.e,=20,B=20

Now again according to the question40% of B=20×40/100=8 i.e=8,C=8

Hence ( A + B ) = 100 + 20 = 120

Now 60% of ( A + B ) = 120 × 60 / 100 = 72

Now 72/8×100=900 i.e, 900%of C

60% of (A+B)=900% of C

you can profit by taking numbersuch as

A=60 or any other number

let's see C=8, therefore 900%of 8 = 8×900/100 = 72 it's proved

may be it helpful to you....