Question

2
17. Twelve men can complete a piece of work in 4
days, while 15 women can complete the same
work in 4 days. 6 men start working on the
job and after working for 2 days, all of them
stopped working. How many women should
be put on the job to complete the remaining
work, if it is to be completed in 3 days?
ta) 15
(b) 18
(c) 22
(d) 25​

Answer 1

Answer:

a)15

Step-by-step explanation:

One man can complete the work in=4×12=48 days

One woman can complete the work in=15×4=60 days

Work done by one man in one day=1/48

Work done by one woman in one day=1/60

Work done by 6 men in one day=1/48×6=6/48

Hence,work done by 6 men in two days=6/48×2=12/48 or 1/4

The remaining work=3/4 or 15/20

Work done by one woman in three days=1/60×3=3/60 or 1/20

So,the number of women required to do the remaining work in three days=15/20÷1/20=15/20×20/1=300/20=15

Hence,the required answer is 15

Answer 2

Correct option is A - 15

12 men can complete a piece of work in 4 days
15 women can complete the same work in 4 days

Let the productivity of men be m and the productivity of women be w

Thus,

12m×4=15w×4
=>4m=5w
=>m= 5/4 w

Total work done by women =60w
Work done by 6 men in 2 days
=6m×2
=6× 5/4 multiply by 2
= 15w


Thus, remaining work =60w−15w
=45w

Let F women complete the remaining job in 3 days

Thus, Fw×3=45w
=>F= 45/3
=>F=15

Thus, 15 women are required to complete the job.