Question

2.1S.. पद्धति में एक मोल परिमाण के कार्बन डाइऑक्साइड की मात्रा कितनी होगी?​

Answer 1

Explanation:

⇝Given :-

➵ A torque of 20Nm is applied on a wheel initially at rest.

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⇝To Find :-

➵ Find the angular momentum of wheel after 3 seconds.

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⇝Solution :-

❒ We know that :

{\large{\red{\bigstar \: \: {\orange{\underbrace{\underline{\blue{\bf{T = \frac{dL}{dt} }}}}}}}}}★

T=

dt

dL

✏ Here :

➳ T = Torque = 20Nm

➳ dL = Change in angular momentum = ?

➳ dt = Time = 3 seconds

❒ Change in angular momentum :

{\large{\longmapsto{\bf{T = \frac{dL}{dt} }}}}⟼T=

dt

dL

{\large{\longmapsto{\bf{20 = \frac{dL}{3} }}}}⟼20=

3

dL

{\large{\longmapsto{\bf{ {dL} = 20 \times 3}}}}⟼dL=20×3

{\large{\green{:{\longmapsto{\red{\overline{\underline{\boxed{\bf{dL = 60 \: N \: m/s}}}}}}}}}}:⟼

dL=60Nm/s

❒ Hence :

➤ Change in angular momentum is 60 N m/s.

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