Question

2.
2
• ಕೆಳಗಿನ ಏಕಕಾಲಿಕ ಸಮೀಕರಣಗಳನ್ನು ಕ್ರೋಮರನ ಪದ್ಧತಿಯಿಂದ ಬಿಡಿಸಿರಿ:
(1) 3x - 4 = 10 ; 4x + 3y = 5 (2) 4x + 3 - 4 = 0; &x =8
(3) x + 2) = -1 ; x - 3y = 12 (4) 6x - 4 = -12 ; 8 - 3y :
(S) 4m + 6 = 54
54 ; 3rm + 2n = 28
(6) 2x + 3 = 2 ; X -​

Answer 1

Answer:

l think that is 3

Explanation:

hope this helps you