Question

2.2*10^-3 moles of Ca(OH)2 weigh​

Answer 1

YᎾUℛ ᎯℕЅᏇℰℛ

$mole = \frac{mass \: (g)}{molar \: mass} \\ \\mass = mole \times molar \: mass \\ molar \: mass \: of \: ca(oh)2 = 74 \\ mass = 2.2 \times {10}^{ - 3} \times 74 \\ mass = 162.8 \times {10}^{ - 3}$

✌️Hope this helps you ✌️

✨Pℒℤ ℳᎯℛᏦ ℐᏆ ᎯЅ ℬℛᎯℐℕℒℐℰЅᏆ ᎯℕЅᏇℰℛ✨

Answer 2

Answer:

39.7*10 power 20

I will explain down

Explanation:

1 mole =6.023*10 power 23

1 mole of ca(oh)2=6.023*10^23*3 ions

1 mole = 18.069*10^23

2.2*10 power-3=x

criss cross multiplication

x=18.069*10^23*2.2*10^-3

x=39.7*10^20

therefore

no.of ions =39.7*10^20