Question

__
༼ ༽ – །༠༽་
པ ས ས ས བ
—— །
—་། __
ཤ 2དྲུག
།
། 2
ཁ2། ་. 2 ︽ག​

Answer 1

Step-by-step explanation:

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Answer 2

$\geq x^{2} \sqrt{x} \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \lim_{n \to \infty} a_n \neq \left[\begin{array}{ccc}1&2&3\\4&5&6\\7&8&9\end{array}\right] \pi$