Question

(√2-2)² = 2 + 4 - 4√2 = 6 - 4√2

(√2+√3)² = 2 + 3 + 2√6 =
5 + √6

Can anyone please explain this briefly
It's urgent!
any unwanted will be reported​

Answer 1

(1.) :-

$by \: using \: (a - {b)}^{2} = {a}^{2} + {b}^{2} - 2ab$

$( \sqrt{2 } - {2})^{2} </p><p></p><p> = ( { \sqrt{2}) }^{2} + ( {2})^{2} - 2 \times \sqrt{2} \times 2$

= (√2-2)² = 2 + 4 - 4√2

= 6 - 4√2

(2.):-

(√2+√3)² = 2 + 3 + 2√6 =

5 + √6

by using (a+b)² = a² + b² + 2ab

(√2+√3)²

=(√2)² +(√3)² +2×√2×√3

=2 + 3 + 2√6

= 5 + √6

hope it is helpful for you

Answer 2

$\huge\tt\underline\red{Que}\underline {s}\underline\purple{tio}\underline{n}\orange {:}$

$\tt ⟹(\sqrt{2}-2)²$

$\huge \underbrace \mathfrak \red{\bigstar Explanation}$

Question number 1:

$\tt ⟹(\sqrt{2}-2)²$

$\tt \boxed {\green{By \:using \:identity\: (a-b)² =a²+b²-2ab}}$

$\tt ⟹(\sqrt{2})²+(2)²-2(\sqrt{2})(2)$

$\tt ⟹2+4-4\sqrt{2}$

$\tt ⟹6 -4\sqrt{2}$

Now, Question number 2:

$\tt ⟹(\sqrt{2}+\sqrt{3})²$

$\tt \boxed {\green{By \:using \:identity\: (a+b)² =a²+b²+2ab}}$

$\tt ⟹(\sqrt{2})²+(\sqrt{3})²+2(\sqrt{2}) (\sqrt{3})$

$\tt ⟹2 + 3 + 2\sqrt{6}$

$\tt ⟹5 + 2\sqrt{6}$

Hope it will help you

plz brainlist