Question

√2+√2+√2+2 cos8Q= KcosQ find k​

Answer 1

Answer:

$3 \sqrt{2 } + 2cos8q = k cosq \\ = 3 \sqrt{2} = k cosq - 2 \cos8q \\ 3 \sqrt{2} = cosq(k - 16) \\( k - 16) = 3 \sqrt{2} \div cosq \\ k = 3 \sqrt{2} \div \cos(q) - 16$