Question

2-2+2-3+2+5÷2×0+6+4+8​

Answer 1

• As per the data given in the question, we have to determine the value of the given expression.

       Given data:- $2-2+2-3+2+5\div2\times0+6+4+8.$

       To find:- the value of the given expression.

       Solution:-  

• Here, we will use BODMAS RULE.  
• BODMAS RULE:- It is a correct order to solve the mathematical expression.
• Where, B stands for bracket
• O stands for of
• D stands for divide
• M stands for multiplication
• A stands for addition
• S stands for subtraction.

      Therefore,

         $=2-2+2-3+2+5\div2\times0+6+4+8\\=2-2+2-3+2+2.5\times0+6+4+8\\=24-5\\=19.$

       Hence, the value will be $19.$

   

   

Answer 2

• As per the data given in the question, we have to find the value of the expression.

          Given data:- $2-2+2-3+2+5 \div 2 \times 0+6+4+8.$

          To find:- Value of given expression.

          Solution:-

• To solve the above equation we will follow the BODMAS rule.

• It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

           where,

           B= bracket

           O= order of power or rules

           D= division

           M= multiplication

           A= addition

           S= subtraction

           Therefore,

        $=2-2+2-3+2+5 \div 2 \times 0+6+4+8 \\=2-2+2-3+2+2.5 \times 0+6+4+8 \\=24-5 \\=19.$

       Hence we will get the value $19.$