√2+√2+√2+sin alpha
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along with steps
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Answer:
ANSWER
sinα−cosα
2
−sinα−cosα
=
2
[
2
1
sinα−
2
1
cosα]
2
[1−
2
1
sinα−
2
1
cosα]
=
cos45
0
sinα−sin45
0
cosα
1−[sin45
0
sinα+cos45
0
cosα]
=
sin(
4
π
−α)
1−[cos(α−
4
π
)]
=
2sin(
8
π
−
2
α
)cos(
8
π
−
2
α
)
2sin
2
(
2
α−π/4
)
=tan(
2
α
−
8
π
)
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