Question

√2+√2+√2+sin alpha
please reply​
along with steps

Answer 1

Answer:

ANSWER

sinα−cosα

2

−sinα−cosα

=

2

[

2

1

sinα−

2

1

cosα]

2

[1−

2

1

sinα−

2

1

cosα]

=

cos45

0

sinα−sin45

0

cosα

1−[sin45

0

sinα+cos45

0

cosα]

=

sin(

4

π

−α)

1−[cos(α−

4

π

)]

=

2sin(

8

π

−

2

α

)cos(

8

π

−

2

α

)

2sin

2

(

2

α−π/4

)

=tan(

2

α

−

8

π

)