Question

2
2
272
X Х
b-c
At is given that (X+1}}/2° = x +1) Ta-1)²(x²+x+1)
(x²+1)²
(x² - 1²
where at +1 and 10 > by c7 4, b and C both are integers
Find the number of possible order pairs of (b, c).​

Answer 1

Step-by-step explanation:

Given equation is (x

2

+1)

2

−x

2

=0

⇒(x

2

)

2

+(1)

2

+2(x)

2

(1)−x

2

=0

⇒(x

2

)

2

+x

2

+1=0

Let x

2

=y

⇒y

2

+1y+1=0

Now, D=b

2

−4ac

⇒D=(1)

2

−4(1)(1)=1−4

⇒D=−3

⇒D<0

So, the given equation y

2

+y+1=0 has no real roots.

∴ the equation $$\left ( x^{2} + 1 \right )^{2} - x^{2} =0$ has no real roots.