Question

. 2х + Зу = 2,
х- 2y = 8.​

Answer 1

Answer :

x = 4 , y = -2

Solution :

Here ,

The given equations are ;

2x + 3y = 2 -------(1)

x - 2y = 8 --------(2)

Let's find the solution of simultaneous equations by substitution method .

Thus ,

Using eq-(2) , we have ;

=> x - 2y = 8

=> x = 8 + 2y -------(3)

Now ,

Substituting x = 8 + 2y in eq-(1) , we get ;

=> 2x + 3y = 2

=> 2(8 + 2y) + 3y = 2

=> 16 + 4y + 3y = 2

=> 4y + 3y = 2 - 16

=> 7y = -14

=> y = -14/7

=> y = -2

Now ,

Substituting y = -2 in eq-(3) , we get ;

=> x = 8 + 2y

=> x = 8 + 2•(-2)

=> x = 8 - 4

=> x = 4

Hence ,

x = 4 , y = -2

Answer 2

Step-by-step explanation:

★ 2x + 3y = 2 ........(Equation 1)

★ x - 2y = 8 ...........(Equation 2)

We get,

• x = 8 + 2y ........(From Equation 2)

★ Substitute the value of x = 8 + 2y in equation (1):

➮ 2x + 3y = 2 (Given equation)

➮ 2(8 + 2y) + 3y = 2

➮ 16 + 4y + 3y = 2

➮ 4y + 3y = 2 - 16

➮ 7y = -14

➮ y = -14/7

➮ y = -2

★ Putting the value of y = -7 in x = 8 + 2y we get,

➮ x = 8 + 2y

➮ x = 8 + 2(-2)

➮ x = 8 + (-4)

➮ x = 8 - 4

➮ x = 4

Therefore,

• x = 4

• y = -2