Math, asked by jsreenivasulu, 6 months ago

2^2*(3^2/2^-2)*3^-1=​

Answers

Answered by ankaiahbollineni39
0

Answer:

16

Step-by-step explanation:

2^2*(3^2/2^-2)3^-2

=2^2(3^2×2^2)×1/3^2

=2^2(2^2)=4×4=16

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