√2/√2+√3-√5 and of this question
Answers
Answered by
0
Step-by-step explanation:
If it were simply
1
√
a
+
√
b
, we would use the conjugate,
and we would multiply by
√
a
−
√
b
√
a
−
√
b
.
Let's try something like that and see if it works. (This is what we do with problems of kinds we have not seen before. Try something and see if it works.)
1
√
2
+
√
3
+
√
5
=
1
√
2
+
(
√
3
+
√
5
)
=
1
[
√
2
+
(
√
3
+
√
5
)
]
[
√
2
−
(
√
3
+
√
5
)
]
[
√
2
−
(
√
3
+
√
5
)
]
=
[
√
2
−
(
√
3
+
√
5
)
]
[
√
2
+
(
√
3
+
√
5
)
]
[
√
2
−
(
√
3
+
√
5
)
]
=
[
√
2
−
(
√
3
+
√
5
)
]
2
−
(
√
3
+
√
5
)
2
=
[
√
2
−
(
√
3
+
√
5
)
]
2
−
(
3
+
2
√
15
+
5
)
=
[
√
2
−
(
√
3
+
√
5
)
]
−
6
−
2
√
15
Answered by
1
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