Question

$(-2^{2})^{-3} \cdot 2^8$?

Answer 1

$\frac{\left(2ab^3\right)^{-1}}{20\left(2^{-1}ba^ 5\right)^2}\left(\frac{4ab^{-1}}{5b}\ .... $=\frac{5 ^2}{4^2\cdot\:10a^{13}b}$=5 24 2· 10 a 13 b ...