Question

2+2÷30×70-60+50+2-2(637+3728-261)​

Answer 1

Given: $2+2\div30\times70-60+50+2-2(637+3728-261)$

We have to solve the above equation.

• By using the Bodmas rule, we are solving the above equation.
• As we know that the Bodmas rule is used to remember the order of operations to be followed while solving expressions in mathematics.

Where,

$\begin{array}{l}\mathrm{B}=\text{brackets}\\\mathrm{O}=\text { order of powers or rules } \\\mathrm{D}=\text { division } \\\mathrm{M}=\text { multiplication } \\\mathrm{A}=\text { addition } \\\mathrm{S}=\text { subtraction }\end{array}$

We are solving in the following way:

We have,

$2+2\div30\times70-60+50+2-2(637+3728-261)$

Solving the above equation further we get,

$\begin{array}{l}=2+2 / 30{\times} 70-60+50+2-2{\times}(4104) \\=2+2 / 30{\times} 70-60+50+2-2{\times} 4104 \\=2+0.066{\times} 70-60+50+2- \\2{\times} 4104 \\=2+4.666-60+50+2-2{\times} 4104 \\=2+4.666-60+50+2-8208 \\=6.66-60+50+2-8208 \\=-53.333+50+2-8208 \\=-3.33+2-8208 \\=-1.33-8208 \\=-8209.333\end{array}$

Hence, the solution of the equation is$-8209.33$.

Answer 2

• As per the data given in the question, we have to find the value of the expression.

       Given data:- $2+2 \div 30 \times 70-60+50+2-2(637+3728-261).$

       To find:- Value of given expression.

       Solution:-

• To solve the above equation we will follow the BODMAS rule.

• It is the rule used to remember the order of operations to be followed while solving expressions in mathematics.

        Therefore,

          $\begin{array}{l}=2+2 / 30 \times 70-60+50+2-2 \times(4104) \\=2+2 / 30 \times 70-60+50+2-2 \times 4104 \\=2+0.066 \times 70-60+50+2- \2 \times 4104 \\=2+4.666-60+50+2-2 \times 4104 \\=2+4.666-60+50+2-8208 \\=6.66-60+50+2-8208 \\=-53.333+50+2-8208 \\=-3.33+2-8208 \\=-1.33-8208 \\=-8209.333\end{array}$

        Hence we will get the value $-8209.333.$