Question

2^2-32z-105 factorise

Answer 1

Answer :
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z² - 32z - 105 

a = 1 

b = -32 

c = -105 

D = b² - 4ac 

= 1024 - 4 x 1 x ( -105)  

= 1024 + 420 

= 1444 

√D = 38

two roots are  -b + √D/2a  , -b -√D/2a 

32 +38 / 2   or 32 - 38 / 2 

70 / 2  or -6/2 

35 or -3 

factors 

(z-35) or (z+3) 

(z-35) (z+3) 
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