Question

2^2-32z-105 splitting the middle term factorise

Answer 1

Answer :
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z² - 32 z - 105

z² -35z + 3z - 105

z(z - 35) + 3(z - 35)

(z - 35) (z+3) ______________________________________________________________
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Answer 2

I assume it to be
z²-32z -105=0

we can write the above equation as,
z²-35z+3z -105=0
z(z-35) +3(z-35)=0
(z-35)(z+3)=0

now, either
z-35=0 OR z+3 =0

therefore,
z=35 OR z =-3

hope this helps