( 2х^2 + 3x-2)^2
plzz answer it
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Step-by-step explanation:
4x^4+12x^3+17x^2+12x+4
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Answer: consider 2x²=a and (3x-2)=b then we have
(a+b)²=a²+2ab+b²
so,
( 2х^2 + 3x-2)^2=(2x²)²+2x(2x²)x(3x-2)+(3x-2)²
=4x⁴+4x²(3x-2)+(9x²-2x3Xx2+4)
=4x⁴+12x³-8x²+9x²-12x+4
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