Question

2-2(3x-y)=10(4-y)-5 =4(y -x)

Answer 1

Given: The term 2-2(3x-y)=10(4-y)-5 =4(y -x)

To find: The value of x and y ?

Solution:

• Now we have given the term:

              2-2(3x-y) = 10(4-y)-5 = 4(y -x)

• Consider first two terms, we get:

              2-2(3x-y) = 10(4-y)-5

              2 - 6x + 2y = 40 - 10y - 5

              - 6x + 2y + 10y = 33

              12y - 6x = 33

              4y - 2x - 11 = 0 ................(i)

• Consider last two terms, we get:

              10(4-y)-5 = 4(y -x)

              40 - 10y - 5 = 4y  - 4x

              35 = 14y - 4x

              17.5 = 7y - 2x    ..............(ii)

• Subtracting (i) from (ii), we get:

                7y - 2x  = 17.5

              - 4y +  2x = - 11

                3y = 6.5

              y = 65/30

              y = 13/6

• Putting the value of y in (i), we get:

              4(13/6) - 2x - 11 = 0

              26/3 - 11 = 2x

              26 - 33 / 3 = 2x

              -7/3 = 2x

              x = -7/6

Answer:

            So the value of x is -7/6 and y is 13/6.