Question

2/2√5- √3+3/2√5+√3 simplify this by rationalizing the denominator<br />​

Answer 1

Answer:

(2/2√5-√3)+(3/2√5+√3)

• [2(2√5+√3)/(2√5-√3)(2√5+√3)]+[3(2√5-√3)/(2√5+√3)(2√5-√3)
• [(4√5+2√3)/(2√5)²-(√3)²]+[(6√5-3√3)/(2√5)²-(√3)²]
• [(4√5+2√3)/4×5-3]+[(6√5-3√3)/4×5-3]
• [(4√5+2√3)/20-3]+[(6√5-3√3)/20-3]
• after canceling 4 & 20 and -3 &-3 we get
• [(√5+2√3)/5-3]+(6√5+√3)/20]
• after canceling 2 from 2 which have subtracted by 5-3 =2we get
• (√5+√3+6√5+√3)/20
• (√5+√3+3√5+√3)/10
• (√5+3√5+2√3)/10
• (√5+3√5+√3)/5