Question

2+2=5 gave me this answer faster

Answer 1

$to \: prove - - > 2 + 2 = 5 \\ \\ as \: we \: know \: that \: = > 2 + 2 = 4 \\ \\ = > 2 + 2 = 4 - \frac{9}{2} + \frac{9}{2} \\ = \sqrt{( {4 - \frac{9}{2}) }^{2} } + \frac{9}{2} \\ = \sqrt{16 - 2 \times 4 \times \frac{9}{2} + ( { \frac{9}{2} )}^{2} } + \frac{9}{2} \\ = \sqrt{16 - 36 + = ({ \frac{9}{2} )}^{2} } + \frac{9}{2} \\ = \sqrt{ - 20 + ({ \frac{9}{2} )}^{2}} + \frac{9}{2} \\ = \sqrt{25 - 45 + ({ \frac{9}{2} )}^{2}} + \frac{9}{2} \\ = \sqrt{ {5}^{2} - 2 \times 5 \times \frac{9}{2} + ({ \frac{9}{2} )}^{2}} + \frac{9}{2} \\ = \sqrt{ {( 5 - \frac{9}{2} )}^{2} } + \frac{9}{2} \\ = 5 - \frac{9}{2} + \frac{9}{2} \\ = 5 \\ \\ so \: 2 + 2 = 5 \: \: (henced \: proved)$