Question

2+2=5 how..............

Answer 1

proof is given above .....

Answer 2

Answer:

This is proved by the method of contradiction.

Step-by-step explanation:

We know,

2+2=4

$So,\ 2+2=4-\frac{9}{2}+\frac{9}{2} \\2+2=\sqrt{(4-\frac{9}{2})^2} +\frac{9}{2} \\2+2=\sqrt{16-2*4*\frac{9}{2}+(\frac{9}{2})^2}+\frac{9}{2} \\2+2=\sqrt{16-36+(\frac{9}{2})^2}+\frac{9}{2} \\2+2=\sqrt{-20+(\frac{9}{2})^2} + \frac{9}{2}\\2+2=\sqrt{25-45+(\frac{9}{2})^2}+\frac{9}{2} \\2+2=\sqrt{(5)^2-2*5*\frac{9}{2}+(\frac{9}{2})^2}+\frac{9}{2}\\2+2=\sqrt{(5-\frac{9}{2})^2}+\frac{9}{2}\\\\\2+2=5-\frac{9}{2}+\frac{9}{2} \\2+2=5\\(Proved)$