Question

(зр+ч) - - 2
2 -6р
5

Answer 1

I don't understand question

Answer 2

Answer:

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Step-by-step explanation:

(3)

Sol. P(A) =

2

5

P(A  B) =

3

20

P(A/(A'  B')) = ?

P(A/(A'  B')) = P(A (A' B'))

P(A' B')

 



= P((A A') (A B'))

P(A B)'   



= P( (A B'))

1 P(A B)

  

 

= P(A B')

3

1

20



 = P(A) p(A B)

17

20

 

=

2 3

5 20

17

20

 =

5

20

17

20 =

5

17

2. For x  R, x  0, x  1, let f0(x)=

1 x

1

 and fn + 1(x) = f0 f(n

(X) , n = 0, 1, 2,ÖÖÖ Then the value of

f100(3) + f1 











3

2

+ f2 











2

3

is equal to :

(1) 3

4

(2) 3