Question

2. 2.82g of glucose (molar mass = 180) is dissolved in 30g of water. The density
of this solution was found to be 1.1g/ml. Calculate
i) Molarity (M) ii) Molality(m) iii) mole fraction of each component.

Answer 1

Answer:

We know that,

The weight of glucose=2.82g

Also,

no. of moles of glucose=n2=1802.82=0.01567

no. of moles of N2O=n1=1830=1.667

Molality=n1n2×m.wtofsolvent1000

=1.6670.01567×181000=0.5222molal

We have moles of glucose (x2)=0.01567

moles of H2O(x1)=1.667

So, mole fraction of glucose

x2=n1+n2n2=(1.667+0.01567)