Question

2.2 dm of lead is to be drawn into a cylindrical wire 0.50 cm in
diameter. The length of the wire is
(a) 110 m (b) 112 m (c) 98 m
(d) 124 m​

Answer 1

Answer:

112m

Step-by-step explanation:

Volume of wire = (2.2*10*10*10) cm^3 = 2200 cm^3.

22/7 * 0.25 * 0.25 * h = 2200

h = (2200 * 7/22 * 1/ 0.25*0.25) cm

Therefore

Length of wire = (11200/100) m = 112 m

Answer 2

Hola mate

Here is your answer -

Radius of the cylindrical wire= 0.50 / 2 = 0.25

And,  

Volume = 2.2 dm^3 = (2.2 . 10 . 10 . 10)cm^3

=2200 cm^3

Now,  

22/7 × 0.25 × 0.25 × h = 2200

h = 11200 / 100 = 112

Hence,

Length of the wire = 112m