Question

2.2 g of a compound of phosphorous and sulphur
has 1.24 g of 'P' in it. Its emperial formula is -​

Answer 1

Answer:

The ratio of weights of P:S is 1.24:[2.2−1.24] = 1.24:0.96.

The molar ratio is

31

1.24

:

32

0.96

=4:3.

Therefore, the formula of the compound is P4S3

.