2, 2 root2, 4....are in GP and 64 is the xth term in GP then x-10=
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here a = 2
and
r = √2
xth term of gp is 64
(a)r^(x-1) 64
2(√2)^(x-1) = 64
2^( (x-1)/2 ) = 32 = 2^5
so
x - 1 = 10
x = 11
now x-10 = 11-10 = 1
and
r = √2
xth term of gp is 64
(a)r^(x-1) 64
2(√2)^(x-1) = 64
2^( (x-1)/2 ) = 32 = 2^5
so
x - 1 = 10
x = 11
now x-10 = 11-10 = 1
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