Question

(√2-√2)whole square ​

Answer 1

Answer:

$( \sqrt{2} - \sqrt{2} ) ^{2} \\ \\ ({x - y})^{2} = {x}^{2} + {y}^{2} - 2xy \\ \\ ({ \sqrt{2}) }^{2} + ({ \sqrt{2} })^{2} - 2 \sqrt{2} \sqrt{2} \\ \\ 2 + 2 - 2 \sqrt{2 \times 2} \\ \\ 4 - 2 \sqrt{4} \\ \\ 4 - 2(2) \\ \\ 4 - 4 \\ \\ 0$

Answer 2

Answer:

0

Step-by-step explanation:

The formula of (a-b)^2 is a^2-2ab+b^2

(√2)^2-2*√2*√2+(√2)^2

2-4+2

0

0 is the answer hope it's helps you..❤️