Question

2.
2 years ago, my age was 4 times the age of my son then. 6 years ago, my age
was twice the square of the age of my son then. Find the present age of my son.​

Answer 1

bhai iske factor nahi ban rahe hai

May be questions me mis print hai ok.

Answer 2

Step-by-step explanation:

Let 2 years ago, son's age be x

So my age(2years ago)= 4.5x

So, 6 years ago,

My age=4.5* -4

Son's age=x-4

B/C

4.5*4=2(x-4)^2) or,

4*^2-41*+72=0

Solving the quadratic, we get-

x=8 or x=2.5 ( Not possible)

So,

my present age of =4.5*+2= 38

My son's present age= x+2

= 10( Answer)...