Math, asked by tanishq3050, 1 year ago

2^2018+2^2017/2^2016+2^2017

Answers

Answered by pulakmath007
1

SOLUTION

TO DETERMINE

 \displaystyle \sf{ \frac{ {2}^{2018} +  {2}^{2017}  }{ {2}^{2016}  +  {2}^{2017} } }

EVALUATION

 \displaystyle \sf{ \frac{ {2}^{2018} +  {2}^{2017}  }{ {2}^{2016}  +  {2}^{2017} } }

 \displaystyle \sf{ =  \frac{ {2}^{2018} +  {2}^{2017}  }{ {2}^{2017}  +  {2}^{2016} } }

 \displaystyle \sf{ =  \frac{ {2}^{2017}  \times (2 + 1)  }{ {2}^{2016} \times  ( 2+ 1) } }

 \displaystyle \sf{ =  \frac{ 3 \times {2}^{2017}    }{3 \times  {2}^{2016} } }

 \displaystyle \sf{ =  \frac{  {2}^{2017}    }{  {2}^{2016} } }

 \displaystyle \sf{ = {2}^{(2017 - 2016)} }

 =  {2}^{1}

 = 2

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