Question

2
2²+2) ax² +212 +32-6​

Answer 1

Answer:

\bold{x=\frac{a}{2},-a} is the value of the quadratic equation \bold{2 x^{2}+a x-a^{2}=0.}

Given:

2 x^{2}+a x-a^{2}=0

To find:

Value of x=?

Solution:

To solve the equation 2 x^{2}+a x-a^{2}=0, we have to first find the value of the “a” in the equation 2 x^{2}+a x-a^{2}=0

We will use the separation method that is finding the common factor we get

2 x^{2}+a x-a^{2}=0

2 x^{2}+2 a x-a x-a^{2}=0

Now subtracting ax from 2ax we get

\begin{array}{l}{2 x(x+a)-a(x+a)=0} \\ {2 x-a, x+a}\end{array}

After solving the quadratic equation for the value of “a” we get the value of: “x” as x=\frac{a}{2},-a

Therefore, the value of the quadratic equation after solving is \bold{x=\frac{a}{2},-a}