Question

2.25 ×10^2 electrons pass from point a to point b through a wire in 10^2 seconds. find the magnitude and direction​

Answer 1

Answer:

2.25e+20 electrons times 1.6021766208e-19 coulombs, for the charge of 1 electron, gives

36.048973968… C of charge total.

Next, divide by time.

36.048973968… C / 60 s = 0.6008162328… C

Finally, reduce to 1 significant figure (unless the “one minute” was 1.0 or 1.00, etc.)

.6 C/s, or .6 A of current.

If this is for a class, I can’t speak for your teacher, but I personally would write that as 600 mA. Your teacher might want .6 A or 600 mA or maybe another significant figure count. From what you typed, it’s 1 sig-fig.