Question

2
27,64, ?216, 343,512
(1) 100 (2) 112
(3) 125 (4) 152​

Answer 1

Answer:

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Step-by-step explanation:

By inspection, this series has the algorithm a(n)=n^3 for each position 1-infinity in the series:

(1) 1^3=2

(2) 2^3=8

(3) 3^3=27

(4) 4^3=64

(5) 5^3=125

(6) 6^3=216

(7) 7^3=343

(8) 8^3=512

(9) 9^3=729

(10) 10^3=

1000

C.H.