Question

2.27
number of protons and (11) the electronic configuration of the ele
Give the number of electrons in the species H), H, and o
(1) An atomic orbital has n = 3. What are the possible values
2.28​

Answer 1

Answer:1

Explanation:

Answer 2

Answer:

sorry, I only know that

Explanation:

(i) Mass of one electron = 9.10939 × 10–31 kg

Number of electrons that weigh 9.10939 × 10–31 kg = 1

Number of electrons that will weigh 1 g = (1 × 10–3 kg)

= 0.1098 × 10–3 + 31

= 0.1098 × 1028

= 1.098 × 1027

(ii) Mass of one electron = 9.10939 × 10–31 kg

Mass of one mole of electron = (6.022 × 1023) × (9.10939 ×10–31 kg)

= 5.48 × 10–7 kg

Charge on one electron = 1.6022 × 10–19 coulomb

Charge on one mole of electron = (1.6022 × 10–19 C) (6.022 × 1023)

= 9.65 × 104 C

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