Question

2.
29. Factorise:x^3-1/x^3-2x+2/x
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Answer 1

Answer:

That's x⁶-2x²+1

now, (x³)²-(2^1/2x)²-(-1)²

I tried different ways but there's actually one way to factories two of the terms of the given expression but remainder would be obtained.......

so, here are all those different methods......

Considering x³=a and (2^1/2x) =b and suppose (-1) =c

would provide

a²-b²-c²

so first method=

(a+b)(a-b) -c² or

second method

a²-(b+c)(b-c)

third method

a²-(b²+c²)

a²-((b+c)²-2bc)

so, (a+b+c)(a-b-c) +2bc

as you can see that the given expression isn't completely divisible and would always leave a remainder in each case

I hope that you might have understood the point by now

so dear, all the best keep hustling and plzz dont forget one thing

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