2.295 g of the oxide of a bivalent metal when dissolved in nitric acid form 3.915 g of the nitrate of the metal. Calculate the atomic weight of the metal?
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Answer:
Explanation:
5 g of oxide contains 4 g of Cu and 1 g of oxygen.
Thus 1 g of oxygen combines with 4 g of Cu.
8 g of oxygen will combine with 8×4=32 g of Cu
Hence, the equivalent weight of copper is 32 g/eq.
Hence the correct option is B.
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