Question

2.295 g of the oxide of a bivalent metal when dissolved in nitric acid form 3.915 g of the nitrate of the metal. Calculate the atomic weight of the metal?....

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

5 g of oxide contains 4 g of Cu and 1 g of oxygen.

Thus 1 g of oxygen combines with 4 g of Cu.

8 g of oxygen will combine with 8×4=32 g of Cu

Hence, the equivalent weight of copper is 32 g/e