Question

(2) (2a² – 3b2 + 4c?) + (62 - a² + c2) +
(c2 + a2 - 62)​

Answer 1

Let's simplify step-by-step.

$\tt2a^2−3b^2+4c+62−a^2+c^2+c^2+a^2−62$

$\tt =2a^2+−3b^2+4c+62+−a^2+c^2+c^2+a^2+−62$

Combine Like Terms:

$\tt =2a^2+−3b^2+4c+62+−a^2+c^2+c^2+a^2+−62$

$\tt =(2a^2+−a^2+a^2)+(−3b^2)+(c^2+c^2)+(4c)+(62+−62)$

$\tt =2a^2+−3b2+2c2+4c$

Answer:

$\tt =2a^2−3b^2+2c^2+4c$

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Answer 2

Step-by-step explanation:

4a^2 - 6b^2 +8c^2 + 62 - a^2 +c^2 + c^2 + a^2 - 62

4a^2 - 6b^2 +10c^2 = 0

2(2a^2 - 3b^2 +5c^2) =0

2a^2 - 3b^2 +5c^2=0