2√2acube+8bcube_27ccube+18√2abc factorise
Answers
Answered by
6
Hi friend
---------------
Your answer
--------------------
FACTORISATION
---------------------------
2√2a³ + 8b³ - 27c³ + 18√2abc
=> (√2a)³ + (2b)³ + (- 3)³ - 3 × (√2a) × (2b) × ( -3c)
=> (√2a + 2b - 3c ) [ (√2a)² + (2b)² + (-3c)² - (√2a)(2b) - (2b)(-3c) - (-3c)(√2a)]
=> (√2a + 2b - 3c)( 2a² + 4b² + 9c² - 2√2ab + 6bc + 3√2ca)
HOPE IT HELPS
#ARCHITECTSEHROLLINS
✯ BRAINLY STAR ✯
---------------
Your answer
--------------------
FACTORISATION
---------------------------
2√2a³ + 8b³ - 27c³ + 18√2abc
=> (√2a)³ + (2b)³ + (- 3)³ - 3 × (√2a) × (2b) × ( -3c)
=> (√2a + 2b - 3c ) [ (√2a)² + (2b)² + (-3c)² - (√2a)(2b) - (2b)(-3c) - (-3c)(√2a)]
=> (√2a + 2b - 3c)( 2a² + 4b² + 9c² - 2√2ab + 6bc + 3√2ca)
HOPE IT HELPS
#ARCHITECTSEHROLLINS
✯ BRAINLY STAR ✯
Similar questions